DSA Flip Bits Problem with Solution in Numerous Language

def maxOnes(A, N):
    max_ones = 0
    max_ones_with_flip = 0
    current_ones = 0

    for num in A:
        if num == 1:
            current_ones += 1
            max_ones_with_flip += 1
        else:
            current_ones = max(current_ones - 1, 0)
            max_ones_with_flip += 1

        max_ones = max(max_ones, current_ones)

    return max(max_ones, max_ones_with_flip)

# Example usage
A = [1, 0, 1, 1, 0, 1, 0, 1]
N = len(A)
result = maxOnes(A, N)
print(result)  # This will output the maximum number of 1's possible after the operation.

using System;

class Program
{
    static int MaxOnes(int[] A, int N)
    {
        int maxOnes = 0;
        int maxOnesWithFlip = 0;
        int currentOnes = 0;

        for (int i = 0; i < N; i++)
        {
            if (A[i] == 1)
            {
                currentOnes++;
                maxOnesWithFlip++;
            }
            else
            {
                currentOnes = Math.Max(currentOnes - 1, 0);
                maxOnesWithFlip++;
            }

            maxOnes = Math.Max(maxOnes, currentOnes);
        }

        return Math.Max(maxOnes, maxOnesWithFlip);
    }

    static void Main(string[] args)
    {
        int[] A = { 1, 0, 1, 1, 0, 1, 0, 1 };
        int N = A.Length;
        int result = MaxOnes(A, N);
        Console.WriteLine(result); // This will output the maximum number of 1's possible after the operation.
    }
}

public class Main {
    public static int maxOnes(int[] A, int N) {
        int maxOnes = 0;
        int maxOnesWithFlip = 0;
        int currentOnes = 0;

        for (int i = 0; i < N; i++) {
            if (A[i] == 1) {
                currentOnes++;
                maxOnesWithFlip++;
            } else {
                currentOnes = Math.max(currentOnes - 1, 0);
                maxOnesWithFlip++;
            }

            maxOnes = Math.max(maxOnes, currentOnes);
        }

        return Math.max(maxOnes, maxOnesWithFlip);
    }

    public static void main(String[] args) {
        int[] A = {1, 0, 1, 1, 0, 1, 0, 1};
        int N = A.length;
        int result = maxOnes(A, N);
        System.out.println(result); // This will output the maximum number of 1's possible after the operation.
    }
}

function maxOnes(A) {
    let maxOnes = 0;
    let maxOnesWithFlip = 0;
    let currentOnes = 0;

    for (let i = 0; i < A.length; i++) {
        if (A[i] === 1) {
            currentOnes++;
            maxOnesWithFlip++;
        } else {
            currentOnes = Math.max(currentOnes - 1, 0);
            maxOnesWithFlip++;
        }

        maxOnes = Math.max(maxOnes, currentOnes);
    }

    return Math.max(maxOnes, maxOnesWithFlip);
}

// Example usage
const A = [1, 0, 1, 1, 0, 1, 0, 1];
const result = maxOnes(A);
console.log(result); // This will output the maximum number of 1's possible after the operation.